In an ap the sum of first 10 terms is -80
WebFeb 9, 2024 · Math Secondary School In an A.P. the sum of first ten terms is –80 and the sum of next ten terms is –280. Find the A.P See answers Advertisement abhi178 Let a is the first term and d is the common difference of AP now use formula, Sn=n/2 {2a+ (n-1) d} now S10=10/2 {2a+ (10-1) d} -80=5 (2a+9d) 2a+9d =-16 --------------- (1) again S20-S10=-280 WebIn the given problem, we have the first and the last term of an A.P. along with the sum of all the terms of A.P. Here, we need to find the common difference of the A.P. Here, The first term of the A.P (a) = 2. The last term of the A.P (l) = 29. Sum of all the terms (S n) = 155. Let the common difference of the A.P. be d.
In an ap the sum of first 10 terms is -80
Did you know?
WebOct 6, 2024 · The formula says that the sum of the first n terms of our arithmetic sequence is equal to n divided by 2 times the sum of twice the beginning term, a, and the product of d, the common... WebNigeria 122 views, 10 likes, 0 loves, 1 comments, 0 shares, Facebook Watch Videos from BCOS TV - Broadcasting Corporation of Oyo State: NEWS AROUND THE...
WebIn an A.P. the sum of first ten terms is 80 and the sum of next ten terms is 280. Find the A.P. Let the first term of AP be ‘a’ and common difference be ‘d’. We know, sum of ‘n’ terms of … WebApr 9, 2024 · The sum of arithmetic progression of n terms requires the following steps: Step 1: Find the first term of an Arithmetic Progression that is a Step 2: Find the common difference between the two consecutive terms; we will get d Step 3: Determine the nth term Step 4: Substitute a, d, n in the formula S n = ( n 2) [ 2 a + ( n − 1) d]
WebThe first term of an AP is 10 and the last term is 28. If the sum of all terms is 190, what is the common difference? A. 5 B. 3 C. 1 D. 2 Answer & Explanation Must Read Arithmetic Progression Articles Arithmetic Progression: Concepts & Tricks Arithmetic Progression: Solved Examples Practice Problems: Level 01 Practice Problems: Level 02 Q.6. . WebWe can conclude that 10, 20, 30…, 500 is an AP with common difference, d = 10. First term, a = 10. Let the number of terms in this AP = n. Using nth term formula, an = a + (n – 1)d. 500 = 10 + (n – 1)10. 490 = (n – 1)10. n – 1 = 49. n = 50. Sum of an AP, Sn = (n/2) [ a + an], here an is the last term, which is given] = (50/2) ×[10 ...
WebApr 4, 2024 · To write the sum of first ‘n’ terms of the AP, use the formula S n = n 2 [ 2 a + ( n − 1) d]. Write equations based on the data given in the question. Simplify the equations to …
WebApr 4, 2024 · To write the sum of first ‘n’ terms of the AP, use the formula S n = n 2 [ 2 a + ( n − 1) d]. Write equations based on the data given in the question. Simplify the equations to calculate the values of variables ‘a’ and ‘d’ and thus, … birthday venue in bgcWebSep 22, 2024 · CBSE Class 10 Answered In an A.P. the sum of first ten terms is - 80 and the sum of next ten terms is - 280. Find the A.P. Asked by Topperlearning User 22 Sep, 2024, … birthday venue in cebu cityWebFor the sum of first 10 terms of this A.P, First term = a Last term = a10 So, we know, a n = a + (n-1)d For the 10 th term ( n = 10), a 10 = a + (10 -1)d = a + 9d So, here we can find the sum of the n terms of the given A.P., using the formula, S n = ( n 2) ( a + l) Where, a = the first term l = the last term So, for the given A.P, birthday venue hire christchurchWebOct 27, 2024 · Answer: The explicit formula for the AP is -2n + 3. 1, -1 , -3, -5, -7, -9......... Step-by-step explanation: The sum of the first n terms = n/2 [2a1 + (n - 1)d] where a1=first term … danube realityWebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 301 = 4n + 3 298 = 4n n = 74.5 But 'n' must be an integer. Hence 301 cannot be a term of the given AP. Answer: 301 cannot be a term of the given AP. danube properties for rentWebAug 10, 2024 · If the sum of the first p terms of an AP is ap 2 + bp, find its common difference. Solution: a p = s p – s p-1 = (ap 2 + bp) - [a (p – 1) 2 + b (p – 1)] = ap 2 + bp – (ap 2 + a – 2ap + bp – b) = ap 2 + bp – ap 2 – a + 2ap – bp + b = 2ap + b-a . = a 1 = 2a + b – a = a + b and a 2 = 4a + b – a = 3a + b ⇒ d = a 2 – a 1 = (3a + b) – (a + b) = 2a danube properties headquartersWebSum of first n terms of an AP Finding number of terms when sum of an arithmetic progression is given Google Classroom The sum of n n terms of an arithmetic sequence is 203 203. The first term is 20 20 and the common difference is 3 3. Find the number of terms, n n, in … danube red juice cherry