WebApr 12, 2024 · As explained in the answers found from the link pasted in the comments, there are a few ways you can solve this. The most efficient would probably be to do the following: separate_rows (DF, val, sep = ", ") You get: # A tibble: 7 × 3 id label val 1 1 A NA 2 2 B 5 3 2 B 10 4 3 C 20 5 4 D 6 6 4 D 7 7 4 D 8 Share Improve this answer Web2 days ago · df1 = df.set_index ('theta').reindex (range (0, 360, 30)) s1 = df1 ['r'].ffill () s2 = df1 ['r'].bfill ().fillna (s1.iat [0]) df = s1.add (s2).div (2).reset_index ().assign (name = 'wind') [df.columns] print (df) name theta r 0 wind 0 10.0 1 wind 30 17.0 2 wind 60 19.0 3 wind 90 14.0 4 wind 120 17.0 5 wind 150 17.5 6 wind 180 17.5 7 wind 210 18.0 …
stack and unstack function in R - DataScience Made Simple
WebApr 8, 2024 · I have a table where only some of the numbers should show digits after the decimal. I saw some examples in which formatC was used to convert the format in the dataframe before passing the data to knitr, but that aproach converts the values to character, and I need them to be numeric so I can specify the comma as the decimal … Web1 day ago · In this example, row 4 and 5 have same value in col1 but different value in col2. Similarly, row 9 and 10 same same value in col1 and different value in col2. I want to remove these rows. The desire output would be >df col1 col2 A g1 A,g1 A g1 C g1 D g4 E g4. I tried df_1<-df %>% arrange(col1) %>% distinct(col1,col2,.keep_all=TRUE) how to save on internet service
r - How to modify decimal digits only on some kable rows, keeping …
WebStack function in R by subsetting or selecting specific columns Lets use the “unstacked_df” data frame to demonstrate stack () function with select argument in R. stack () function … WebOct 29, 2024 · Often you may want to get the row numbers in a data frame in R that contain a certain value. Fortunately this is easy to do using the which() function. This tutorial … WebJul 28, 2024 · This function returns the minimum n rows of the dataframe based on a column. Syntax: dataframe %>% slice_min(column, n ) Where dataframe is the input … how to save on heating bills this winter