C s + o2 g → co2 g δhf -393.5 kj/mol

WebC(graphite) + O 2 (g) → CO 2 (g) ΔH o rxn = -393.5 kJ/mol H 2 (g) + 0.5 O 2 (g) → H 2 O(l) ΔH o rxn = = -285.8 kJ/mol 2C 2 H 6 (g) + 7O 2 (g) → 4CO 2 (g) + 6H 2 O(l) ΔH o rxn = … WebJul 24, 2024 · The standard enthalpy of formation of carbon disulfide (CS2) from it's elements is; ΔHorxn = 85.3kJ/mol. To calculate the standard enthalpy of formation of …

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Web摘要 在任何等温过程中系统的内能不变 对于内能是体系状态的单值函数概念,错误理解是A体系处于一定的状态,具有一定 23下列说法不符合热力学第一定律的是() A在孤立系统内发生的任 某物质溶解在互不相溶的两液相 内能是体系状态的单值函数概念 9在温度为298.15K的恒温浴中,一理想气体发生不可逆 ... WebQuestion: What is the value for ΔH for the following reaction? CS2 (l) + 2 O2 (g) → CO2 (g) + 2 SO2 (g) Given: C (s) + O2 (g) → CO2 (g); ΔHf = -393.5 kJ/mol S (s) + O2 (g) → … green shelf food https://tumblebunnies.net

In the reaction CS2 (l) + 3O2 (g) → CO2 (g) + 2SO2 (g) ΔH = –265 …

WebOct 1, 2024 · Since only one O2 is in the reaction, multiply the reaction by 2 to get the second O2. This doubles the ΔHf value. Combining these equations gives. 2 S(s) + C(s) + \(3 O_2(g)\) → \(CO_2(g)\) + \(SO_2(g)\) This equation has the product side needed in the problem but contains extra two S and one C atom on the reactant side. WebJun 17, 2024 · We rearranging and add equations (1, 2, and 3) in such a way as to end up with the needed equation: equation (1) be as it is: (1) C (graphite) + O₂ (g) → CO₂ (g), ΔHf₁° = -393.5 kJ/mol . equation (2) should be multiplied by (2) and also the value of ΔHf₂°: (2) 2H2 (g) + O₂ (g) → 2H₂O (l), ΔHf₂° = 2x (-285.8 kJ/mol ). WebMar 14, 2024 · Answers. If chemical equations are combined, their energy changes are also combined. Δ H = 65.6 kJ. Δ H = −131.2 kJ. Δ H = 88 kJ. Δ H = −220 kJ. Δ H = 570 kJ. … green shell 07093

Find the standard enthalpy of formation of ethylene, C2H4 (g), …

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C s + o2 g → co2 g δhf -393.5 kj/mol

Chm Exam2 (A) Flashcards Quizlet

WebScribd es red social de lectura y publicación más importante del mundo. WebA) 2 C (s, graphite) + 2 H2 (g) → C2H4 (g) B) N2 (g) + O2 (g) → 2 NO (g) C) 2 H2 (g) + O2 (g) → 2 H2O (l) D) 2 H2 (g) + O2 (g) → 2 H2O (g) E) all of the above A 2) Given the data …

C s + o2 g → co2 g δhf -393.5 kj/mol

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WebApr 1, 2024 · In the reaction CS2 (l) + 3O2 (g) → CO2 (g) + 2SO2 (g) ΔH = –265 kcal The enthalpies of formation of CO2 and SO2 are both negative and are in the ratio 4 : 3. The enthalpy of formation of CS2 is + 26 kcal/mol. Calculate the enthalpy of formation of SO2 . (A) – 90 kcal/mol (B) – 52 kcal/mol (C) – 78 kcal/mol (D) – 71.7 kcal/mol WebMar 25, 2015 · To solve this problem, we use Hess's Law. Our target equation has C(s) on the left hand side, so we re-write equation 1: 1. C(s) + O₂(g) → CO₂(g); #ΔH = "-393 kJ"# Our target equation has CO(g) on …

WebJan 30, 2024 · Explanation: ENTHALPY OF REACTION [1ΔHf(CO2 (g)) + 2ΔHf(SO2 (g))] - [1ΔHf(CS2 (ℓ)) + 3ΔHf(O2 (g))] [1(-393.51) + 2(-296.83)] - [1(89.7) + 3(0)] = -1076.87 kJ

WebAnswer: DU= +13 KJ Explanation: Pa brainliest po plsss :< 13. For the reaction 2NaHCO3 → Na2CO3 + CO2 + H2O ∆H = 129.37 kJ/mole Find the standard heat of formation of NaHCO3 given the following ∆H of formation: Na2CO3 = -1,130.94 kJ/mol; CO2 = -393.5 kJ/mol; H2O = -241.8 kJ/mol. Answer: Chemistry 5 points 5.0 2 Answer shineri1234 • … Webdetermine the constant pressure heat of the reaction. The following data may be helpful C (s) + O 2 (g) → CO 2 (g); ΔH f =-393.5 kJ/mol S (s) + O 2 (g) → SO 2 (g); ΔH f =-296.8 kJ/mol C (s) + 2S (s) → CS 2 (g); ΔH f =87.9 kJ/mol Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border

WebCalculate ∆G° for the combustion of ethane2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(l) With the following ∆G°f:C2H6(g) = -32.86 kJ/molCO2(g) = -394.4 kJ/molH2O(l) = -237.2 kJ/mol arrow_forward The reaction for cobalt oxide reduction using CO is given as: CoO + CO = Co + CO2 ΔG°=-48500 + 4.96T J/mol Is it possible to reduce CoO at 1062 oC ...

WebConsider the following thermochemical equations. PCl5 (s)→PCl3 (g)+Cl2 (g)2P (s)+3Cl2 (g)→2PCl3 (g)ΔH∘rxnΔH∘rxn=87.9kJmol=−574kJmol. Using this data, determine the … fmovies infinity poolWebFeb 20, 2011 · more. With Hess's Law though, it works two ways: 1. You use the molar enthalpies of the products and reactions with the number of molecules in the balanced equation to find the change … fmovies icarly rebootWebMOL Consolidation Service (MCS), the global logistics arm of MOL Group heaequartered in Tokyo Japan. We specialize in providing customers the innovative and end-to-end … fmovies how to train your dragon 2WebCompare the amounts of energy that can be obtained per gram of C3H8 (g) and per gram of gasoline, assuming that gasoline is pure octane, C8H18 (l). (See Example 7-11.) Look up the boiling point of propane. What disadvantages are there to using propane instead of gasoline as a fuel? arrow_forward f movies.ioWeb3 H 2 (g) + 3/2 O 2 (g) → 3 H 2 O(l) Δ r H° = –857.4kJ/mol-rxn (Fe 2 O 3 (s) + 3 H 2 O(l) → 2 Fe(OH) 3 (s) Δ r H° = +288.6 kJ/mol-rxn) Reverse Equation or ( * -1) 2 Fe(OH) 3 (s) → … fmovies invincibleWebThe official website of Kendall-Jackson Wines located in Sonoma County. Produces award-winning wines from premier California vineyards. Explore our online store, wine … green shell battle catsWebAug 6, 2024 · Calculate the standard enthalpy of combustion of propane Given the following data (1) C (s) + O2 (g) ==> CO2 (g) ΔHθ = -393 kJ/mol-1 (2) H2 (g) + 1/2O2 (g) ==> H2O (l) ΔHθ = -286 kJ/mol-1 (3) 3C (s) + 4H2 (g) ==> C3H8 (g) ΔHθ = -104 kJ/mol-1 Calculate the standard enthalpy of combustion of propane Follow • 2 Add comment … fmovies is down